Exponentials and Logarithms

A LevelAQAEdexcelOCR

Exponentials and Logarithms

A sum such as 4+3=74+3=7 has two inverses: 73=47-3=4 and 74=37-4=3.

A product such as 8×6=488times6=48 has two inverses: 48÷6=848div6=8 and 48÷8=648div8=6.

An exponential (power) such as 34=813^{4}=81 has an inverse of the fourth root: 814=3sqrt[4]{81}=3. But for the pattern to continue there must be another inverse – an operation involving 8181 and 33 to get back to 44.

This other inverse is the logarithm.

A LevelAQAEdexcelOCR

Logarithms are the Inverse of Exponentials

loga(b)=clog_{a}(b)=c means that ac=ba^{c}=b

a1=aa^{1}=a for any aa so loga(a)=1log_{a}(a)=1

a0=1a^{0}=1 for any aa so loga(1)=0log_{a}(1)=0

 

Example: log3(81)=4log_{3}(81)=4 because 34=813^{4}=81

 

We also have other rules:

loga(x)+loga(y)=loga(xy)log_{a}(x)+log_{a}(y)=log_{a}(xy)

loga(x)loga(y)=loga(xy)log_{a}(x)-log_{a}(y)=log_{a}left(dfrac{x}{y}right)

loga(xn)=nloga(x)log_{a}(x^{n})=nlog_{a}(x)

loga(x)=logb(x)logb(a)log_{a}(x)=dfrac{log_{b}(x)}{log_{b}(a)}

 

Note: The little number after the logtext{log} is called the base. The most common base is 1010, but this is usually left out – i.e. for log10text{log}_{10} we just write logtext{log}.

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Using Logarithms and Exponentials to Solve Equations

We can use the rules above – called the laws of logarithms – to solve equations that involve exponentials.

 

Example: 34x=53^{4x}=5

log(34x)=log(5)log(3^{4x})=log(5)

4xlog(3)=log(5)4xlog(3)=log(5)

x=log(5)4log(3)=0.366begin{aligned}x&=dfrac{log(5)}{4log(3)}[1.2em]&=0.366end{aligned}

Note: The base of the logarithm was not given in this example. This is because we would get the same answer using any base.

 

On the flipside, we can use exponentials to solve equations involving logarithms.

Example: 6log4(x)=176log_{4}(x)=17

log4(x)=176log_{4}(x)=dfrac{17}{6}

x=4176=50.8begin{aligned}x&=4^{frac{17}{6}}[1.2em]&=50.8end{aligned}

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Graphs of Exponentials

An exponential graph is a graph of the function y=axy=a^{x} for some a>0a>0. They all have the same basic shape. If a>1a>1 then yy increases as xx increases. If a<1a<1 then yy decreases as xx increases. Larger aa gives faster increase if a>1a>1 while smaller aa gives faster decrease if a<1a<1.

Note: Exponential graphs never reach 0mathbf{0}.

On the left graph is y=2xy=2^{x}, y=3xy=3^{x} and y=4xy=4^{x}.

On the right graph is y=(12)xy=left(dfrac{1}{2}right)^{x}, y=(13)xy=left(dfrac{1}{3}right)^{x} and y=(14)xy=left(dfrac{1}{4}right)^{x}.

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Exponentials and Logarithms Example Questions

Question 1: Write the following in logarithm notation:

a) 73=3437^{3}=343

b) 54=6255^{4}=625

c) 216=655362^{16}=65536

d) 72913=9729^{frac{1}{3}}=9

e) 220=122^{0}=1

[5 marks]

A Level AQAEdexcelOCR

a) log7(343)=3log_{7}(343)=3

b) log5(625)=4log_{5}(625)=4

c) log2(65536)=16log_{2}(65536)=16

d) log729(9)=13log_{729}(9)=dfrac{1}{3}

e) log22(1)=0log_{22}(1)=0

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Question 2: Evaluate:

a) log2(16)log_{2}(16)

b) log5(125)log_{5}(125)

c) log3(243)log_{3}(243)

d) log14(116)log_{frac{1}{4}}left(dfrac{1}{16}right)

[4 marks]

A Level AQAEdexcelOCR

a) 44 because 24=162^{4}=16

b) 33 because 53=1255^{3}=125

c) 55 because 35=2433^{5}=243

d) 22 because (14)2=116left(dfrac{1}{4}right)^{2}=dfrac{1}{16}

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Question 3: Write these expressions as a single logarithm:

a) loga(12)+loga(6)log_{a}(12)+log_{a}(6)

b) 2logb(5)+logb(4)2log_{b}(5)+log_{b}(4)

c) 3log6(2)+12log6(9)3log_{6}(2)+dfrac{1}{2}log_{6}(9)

[3 marks]

A Level AQAEdexcelOCR

a)

loga(12)+loga(6)=loga(12×6)=loga(72)begin{aligned}log_{a}(12)+log_{a}(6)&=log_{a}(12times6)[1.2em]&=log_{a}(72)end{aligned}

 

b)

2logb(5)+logb(4)=logb(52)+logb(4)=logb(25)+logb(4)=logb(25×4)=logb(100)begin{aligned}2log_{b}(5)+log_{b}(4)&=log_{b}(5^{2})+log_{b}(4)[1.2em]&=log_{b}(25)+log_{b}(4)[1.2em]&=log_{b}(25times4)[1.2em]&=log_{b}(100)end{aligned}

 

c)

3log6(2)+12log6(9)=log6(23)+log6(912)=log6(8)+log6(3)=log6(8×3)=log6(24)begin{aligned}3log_{6}(2)+dfrac{1}{2}log_{6}(9)&=log_{6}(2^{3})+log_{6}(9^{frac{1}{2}})[1.2em]&=log_{6}(8)+log_{6}(3)[1.2em]&=log_{6}(8times3)[1.2em]&=log_{6}(24)end{aligned}

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Question 4: Solve 67x=386^{7x}=38, giving your answer to 33 significant figures.

[2 marks]

A Level AQAEdexcelOCR

67x=386^{7x}=38

7x=log6(38)7x=log_{6}(38)

x=17log6(38)x=dfrac{1}{7}log_{6}(38)

x=0.290x=0.290

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Question 5: Solve log6(x2)+log6(x7)=2log_{6}(x-2)+log_{6}(x-7)=2

[4 marks]

A Level AQAEdexcelOCR

log6(x2)+log6(x7)=2log_{6}(x-2)+log_{6}(x-7)=2

log6((x2)(x7))=2log_{6}((x-2)(x-7))=2

(x2)(x7)=62(x-2)(x-7)=6^{2}

x29x+14=36x^{2}-9x+14=36

x29x22=0x^{2}-9x-22=0

(x11)(x+2)=0(x-11)(x+2)=0

x=11x=11 or x=2x=-2

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Specification Points Covered

F1 – Know and use the function axa^x and its graph, where aa is positive
Know and use the function exe^x and its graph
F2 – Know that the gradient of ekxe^{kx} is equal to kekxke^{kx} and hence understand why the exponential model is suitable in many applications
F3 – Know and use the definition of logaxlog_{a}{x} as the inverse of axa^x, where aa is positive and x0x ≥ 0
Know and use the function lnxln{x} and its graph
Know and use lnxln{x} as the inverse function of exe^x
F4 – Understand and use the laws of logarithms:
logax+logay=loga(xy)log_{a}{x} + log_{a}{y} = log{a}{(xy)}; logaxlogay=(xy)log_{a}{x}-log_{a}{y}={left(dfrac{x}{y}right)}; klogax=logaxkklog_{a}{x}=log_{a}{x^k}
including, for example, k=1k=-1 and k=12k=-dfrac{1}{2}
F5 – Solve equations of the form ax=ba^x=b