Reciprocal Trig Functions

A LevelAQAEdexcelOCR

Reciprocal Trig Functions

Remember how we said that sin1sin ^{-1}, cos1cos ^{-1} and tan1tan ^{-1} aren’t quite the same as 1sindfrac{1}{textcolor{blue}{sin}}, 1cosdfrac{1}{textcolor{limegreen}{cos}} and 1tandfrac{1}{textcolor{red}{tan}}? Here’s why…

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Introducing cosecmathbf{cosec}, secmathbf{sec} and cotmathbf{cot}

We have three definitions, now:

  • Cosecant: cosecx=1sinxtextcolor{blue}{cosec x} = dfrac{1}{textcolor{blue}{sin x}}
  • Secant: secx=1cosxtextcolor{limegreen}{sec x} = dfrac{1}{textcolor{limegreen}{cos x}}
  • Cotangent: cotx=1tanxtextcolor{orange}{cot x} = dfrac{1}{textcolor{red}{tan x}}

We’ve given these three reciprocal functions a special name so we don’t get them confused with the inverse functions.

The easiest way to remember which is which, is to look at the third letter of each function, so, Cosecant =1sin= dfrac{1}{textcolor{blue}{sin}}, Secant =1cos= dfrac{1}{textcolor{limegreen}{cos}} and Cotangent =1tan= dfrac{1}{textcolor{red}{tan}}.

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In Graphical Form

Now, we’ll represent the graph of y=cosecxtextcolor{blue}{y = cosec x}:

Notice how there are now asymptotes at x=180°,0°,180°x = -180°, 0°, 180°.

Well, cosecx=1sinxtextcolor{blue}{cosec x} = dfrac{1}{sin x}, so it will not have values where sinx=0°sin x = 0°, i.e. where x=180°,0°,180°x = -180°, 0°, 180°.

Notice, also, how there are no values between y=1y = 1 and y=1y = -1. Think on that for a while…

 

Anyway, here’s the graph for y=secxtextcolor{limegreen}{y = sec x}:

See how the asymptotes are now at x=270°,90°,90°,270°x = -270°, -90°, 90°, 270°. Again, this is because we’ll find that cosx=0cos x = 0 at these points.

Again, there are no values between y=1y = 1 and y=1y = -1

 

To complete the set, here’s y=cotxtextcolor{orange}{y = cot x}:

This time, there are no undefined values for yy, but we do have vertical asymptotes at x=180°,0°,180°x = -180°, 0°, 180° again.

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Domains, Ranges and Key Values

You might want to reference from this table of ranges and domains:

and here’s some key points that you might need to know.

In case you were wondering, (1,1)(-1,1) means the value is between but not including 1-1 and 11.

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Reciprocal Trig Functions Example Questions

Question 1: Solve secx=2sec x = 2 for all values of xx in the range 0°x720°0° leq x leq 720°.

[2 marks]

A Level AQAEdexcelOCR

secx=2sec x = 2 means that cosx=12cos x = dfrac{1}{2}, which has solutions at x=60°,300°,420°,660°x = 60°, 300°, 420°, 660°.

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Question 2: Briefly explain why cosecxcosec x and secxsec x have no values in the range (1,1)(-1,1).

[2 marks]

A Level AQAEdexcelOCR

cosecx=1sinxcosec x = dfrac{1}{sin x} and secx=1cosxsec x = dfrac{1}{cos x}.

 

Since sinxsin x and cosxcos x have a minimum of 1-1 and maximum of 11, we conclude that cosecxcosec x and secxsec x have a positive minimum of 11=1dfrac{1}{1} = 1, and a negative maximum of 11=1dfrac{1}{-1} = -1.

 

To have cosecxcosec x or secxsec x between 1-1 and 11, we require sinxsin x or cosxcos x to be greater than 11, or less than 1-1, which is not possible.

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Question 3: Solve 3secx=cosecxsqrt{3}sec x = cosec x for πxπ-pi leq x leq pi.

[3 marks]

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Rewrite this as

3cosx=1sinxdfrac{sqrt{3}}{cos x} = dfrac{1}{sin x}

We can rearrange to get

tanx=13tan x = dfrac{1}{sqrt{3}}

This gives

x=tan113=5π6,π6x = tan ^{-1}dfrac{1}{sqrt{3}} = dfrac{-5pi}{6}, dfrac{pi}{6}

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Specification Points Covered

E4 – Understand and use the definitions of secant, cosecant and cotangent and of arcsin, arccos and arctan; their relationships to sine, cosine and tangent; understanding of their graphs; their ranges and domains