Solving Inequalities

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Solving Inequalities

Inequalities are not always presented to us in a straight forward way. More often than not, they’re all jumbled up – like equations often are – and therefore they need to be rearranged and solved.

Make sure you are happy with the following topics before continuing.

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Type 1: Listing values

xx is an integer such that 1x<4-1leq x lt 4. List all numbers that satisfy this inequality.

For such questions you need consider if the inequalities are inclusive or strict, in this case we have,

xx takes any value greater then or equal to 1-1       and        xx takes any value less than 44

Hence, the integers that satisfy the inequality are: 1,0,1,2,3-1,0,1,2,3

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Type 2: Solving Inequalities Basic

Solve the inequality 5a4>2a+85a – 4 > 2a + 8

Firstly, add 44 to both sides of the inequality to get,

(+4)5a4>2a+85a>2a+12begin{aligned}(textcolor{maroon}{+4}),,,,,,,,, 5a -4 &gt 2a+8 5a &gt 2a+12 end{aligned}

Then, subtract 2a2a from both sides to get,

(2a)5a>2a+12 3a>12begin{aligned}(textcolor{maroon}{-2a}),,,,,,,,, 5a &gt 2a+12  3a &gt 12 end{aligned}

Finally, divide both sides by 33 to get,

(÷3)3a>12a>4begin{aligned}(textcolor{maroon}{div 3}),,,,,,,,, 3a &gt 12 a &gt 4 end{aligned}

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Type 3: Solving Inequalities 2 signs

Solve the inequality 5<2x3< 135 lt 2x-3 lt  13

Firstly, add 33 to each side of the inequality,

(Remember what you do to one side you do to all sides,  even if there are 33 sides), to get

(+3)5<2x3<138 <2x<16begin{aligned}(textcolor{maroon}{+3}),,,,,,,,, 5& lt 2x-3 lt 13 8  &lt 2x lt 16 end{aligned}

Finally, divide both sides by 22 to get,

(÷2)8<2x <16 4<x<8begin{aligned}(textcolor{maroon}{div 2}),,,,,,,,, 8 lt 2x&  lt 16  4 lt x& lt 8 end{aligned}

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Type 4: Multiplying and Dividing by a Negative Number 

When rearranging an inequality, you are performing the same operation to both sides of the inequality without changing it (just like as you would with an equation) but with one exception:

If you multiply or divide by a negative number, then the inequality sign changes direction

For example, if we have to solve the inequality 2x>4-2x gt 4, we have to divide both sides by 2-2,

(÷2)2x>4x<2begin{aligned}(textcolor{maroon}{div -2}),,,,,,,,, -2x &gt 4 x &lt -2 end{aligned}

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Level 4-5GCSEAQAEdexcelOCRWJECEdexcel iGCSE

Example

Solve the inequality 4x+42>xdfrac{4x+4}{2} > x

[3 marks]

We need to get rid of the fraction first by multiplying by 22

4x+4>2x{4x+4} > 2x

Then subtract 4x4x

4>2x4 > -2x

Then divide by 2-2

2<x-2 < x

Remember the sign changes direction when multiplying or dividing by a negative number.

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Solving Inequalities Example Questions

Question 1: Solve the inequality 73k>5k+127 – 3k > -5k + 12

[2 marks]

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We solve this inequality by simply rearranging it to make k the subject,

 

 73k>5k+127+2k>12 2k>5k>52begin{aligned}7 – 3k &> -5k + 12 7 +2k&> 12  2k&>5 k&>dfrac{5}{2}end{aligned}

 

Hence kk can take any value greater than 52dfrac{5}{2}

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Question 2: Solve the inequality 5x14>3xdfrac{5x-1}{4} > 3x

[3 marks]

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We solve this inequality by simply rearranging it to make x the subject,

 

 5x14>3x5x1>12x 1>7xx<17begin{aligned}dfrac{5x-1}{4} &> 3x 5x-1&> 12x  -1&>7x x&<-dfrac{1}{7}end{aligned}

 

Hence kk can take any value less than 17-dfrac{1}{7}

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Question 3: Solve the inequality 2x+5>3x22x+5 > 3x-2

[2 marks]

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We solve this inequality by simply rearranging it to make xx  the subject,

 

 2x+5>3x27>x x<7begin{aligned}2x+5 &> 3x-2 7& > x  x&<7end{aligned}

Hence xx can take any value less than 77

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Question 4: Find the range of values that satisfy the inequality, 43x194-3xleq19

[3 marks]

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We solve this inequality by simply rearranging it to make xx the subject in the center of the inequality,

 

 43x193x153x15 x5begin{aligned}4-3x&leq19 -3x&leq 15 3x&geq -15  x&geq-5end{aligned}

 

Hence xx can take any value greater or equal to 5-5

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Question 5: Find the range of values that satisfy the inequality 5<2x3<10-5<2x-3<10

[2 marks]

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We solve this inequality by simply rearranging it to make x the subject in the center of the inequality,

 

 5<2x3<102<2x<13 1<x<132begin{aligned}-5<2x&-3<10 -2<2x&<13  -1<x&<frac{13}{2}end{aligned}

 

Hence xx can take any value greater than 1-1 and less than 132dfrac{13}{2}

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Specification Points Covered

Algebra – 22. solve linear inequalities in one or two variable(s), and quadratic inequalities in one variable; represent the solution set on a number line, using set notation and on a graph

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