The Difference of Two Squares

GCSELevel 6-7AQACambridge iGCSEEdexcelEdexcel iGCSEOCRWJEC

The Difference of Two Squares

The difference of two squares is precisely that. One squared thing subtracted from another squared thing. This means they are straightforward to factorise. Make sure your happy with the following topics before continuing.

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Difference of Two Squares Formula

The trick to factorising the difference of two squares is to use the formula,

a2b2=(a+b)(ab)textcolor{blue}{a^2 -b^2 = (a+b)(a-b)}

This can be used in either direction to factorise or expand such expressions quickly. To show that this works, we will expand the two brackets of the general formula.

(a+b)(ab)=a2+ababb2=a2b2begin{aligned} textcolor{blue}{(a+b)(a-b)} & =textcolor{black}{ a^2 +cancel{ab} – cancel{ab} -b^2 } &= textcolor{blue}{a^2 -b^2} end{aligned}

The negative sign arises as you are multiplying a negative by a positive thus the result is negative. As you can see the two ‘cross terms’ involving both aa and bb cancel, so we are left with just the square terms.

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE
Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Example 1: Factorising a Simple Quadratic

Factorise x29x^2 – 9.

[2 marks]

Identifying that this is a difference of two squares, aa and bb are simply the square roots of x2x^2 and 99 respectively. Hence a=x2=xa=sqrt{x^2}=x and b=9=3b=sqrt{9}=3. So the factorisation is,

(x+3)(x3)(x+3)(x-3)

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Example 2: Removing a Common Factor

Factorise 4x2100y24x^2 – 100y^2.

[3 marks]

This is still a question involving the difference of two squares however a factor of 44 has to be taken out first,

4x2100y2=4(x225y2)4x^2 – 100y^2 = 4(x^2-25y^2)

Now we can find aa and bb by taking the square roots of x2x^2 and 25y225y^2 respectively. Hence a=x2=xa=sqrt{x^2}=x and b=25y2=5yb=sqrt{25y^2}=5y. So the factorisation is,

4(x+5y)(x5y)4(x+5y)(x-5y)

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Example 3: Factorising a Quadratic involving Surds

Factorise y27y^2 – 7.

[2 marks]

In some cases the values we find for aa or bb will be a surd (non-terminating square root) . In this instance a=y2=ya=sqrt{y^2}=y and b=7=7b=sqrt{7}=sqrt{7}. So the factorisation is,

(y+7)(y7)(y+sqrt{7})(y-sqrt{7})

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

The Difference of Two Squares Example Questions

Question 1: 

Factorise 9x249y29x^2 – 49y^2

[3 marks]

Level 6-7GCSE AQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Identifying that both of the coefficients of each term are square numbers, then the square roots are a=9x2=3xa=sqrt{9x^2}=3x and b=49y2=7yb=sqrt{49y^2}=7y. So the factorisation is,

(3x+7y)(3x7y)(3x+7y)(3x-7y)

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Question 2:

Factorise 2x282x^2 – 8

[3 marks]

Level 6-7GCSE AQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Here we can remove a factor of 22 first so,

2x28=2(x24)2x^2 – 8 =2(x^2 – 4)

Thus the factorisation is,

2(x+2)(x2)2(x + 2)(x – 2)

 

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Question 3:

Solve 99298299^2-98^2 without using a calculator.

[2 marks]

Level 8-9GCSE AQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

This is a difference of two squares so we can apply the formula the same way,

 

992982=(99+98)(9998)=(197)(1)=19799^2-98^2=(99+98)(99-98) = (197)(1)=197

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Specification Points Covered

Algebra – 4. simplify and manipulate algebraic expressions (including those involving surds and algebraic fractions) by:

  • collecting like terms
  • multiplying a single term over a bracket
  • taking out common factors
  • expanding products of two or more binomials
  • factorising quadratic expressions of the form x2+bx+cx^2 + bx + c, including the
  • difference of two squares; factorising quadratic expressions of the form ax2+bx+cax^2 + bx + c
  • simplifying expressions involving sums, products and powers, including the laws of indices

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